a^2-19a+77=0

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Solution for a^2-19a+77=0 equation: 



a^2-19a+77=0

a = 1; b = -19; c = +77;
Δ = b2-4ac
Δ = -192-4·1·77
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{53}}{2*1}=\frac{19-\sqrt{53}}{2}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{53}}{2*1}=\frac{19+\sqrt{53}}{2}
$

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